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n^2=3/25
We move all terms to the left:
n^2-(3/25)=0
We add all the numbers together, and all the variables
n^2-(+3/25)=0
We get rid of parentheses
n^2-3/25=0
We multiply all the terms by the denominator
n^2*25-3=0
Wy multiply elements
25n^2-3=0
a = 25; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·25·(-3)
Δ = 300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{300}=\sqrt{100*3}=\sqrt{100}*\sqrt{3}=10\sqrt{3}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{3}}{2*25}=\frac{0-10\sqrt{3}}{50} =-\frac{10\sqrt{3}}{50} =-\frac{\sqrt{3}}{5} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{3}}{2*25}=\frac{0+10\sqrt{3}}{50} =\frac{10\sqrt{3}}{50} =\frac{\sqrt{3}}{5} $
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